MAD 4401  Homework

                        Fall  2011
 

   Note: Homework is due by 5:00 p.m. on the due date. Late homework
                is not accepted.

    Important:    The numbers of homework problems listed are in the 9th edition of the book. 

                          The problems in parenthesis are in the 8th edition. If there are no problems in parenthesis -

                         the numbers are the same in 8th and 9th editions.

                     
 
 
 
 
 Number   Due Date  Section Numbers  Problem Numbers
        1.   Sep 7
 Section 1.2 
 Section 1.3		  5f, 13c, 15c
 6c, 7b
        2.   Sep. 14
  Section  2.1
 Section  2.2
  3c, 5b, 10b, 14
 7, 11f
        3.   Sep 21
  Section  2.3
 Section 2.4
 6c, 8 and 10 with 6c, 29 c,d
6a,9a
        4.  Sep 28
 
 Section 3.1
 

2a, 4 with 2a, 5a,13d(19d)
 
        5.  Oct 5
 Section 3.3 (3.2)
 Section 3.4 (3.3)
  3b, 5b, 9a,b,12, 16, 17
  1c,3c
        6.  Oct. 12
 
 no hmwk this week 
        7.   Oct 19
  Section 3.5 (3.4)
 Section 4.1 		2,12,13
1b, 3b, 5a, 7a
        8.   Oct. 26
 Section 4.3
 Section 4.4 		 1d, 5 and 9 with 1d, 18
8 a,b, 9, 11a
        9.   Nov. 2
   Section 4.7
  Section 8.1 		2 with 1h, 5
5 a,d,e
      10.   Nov. 9
  Section 5.1
 Section 5.2
 Section 5.3
  3a
 5a, 7a, 10c
 5a, 6b, 7 with 5a
      11.   Nov. 16
 no hmwk this week
      12.   Dec. 2
  Section 6.1
 Section 6.2
 Section 6.5
   3a, 5d,10
  9b,13 (with 9b), 17 (with 9b)
  3d, 6a 9c
      13.  
 
  

 

               Answers to Homework Problems
 

   Section 2.1:  Problem 6: The Bisection Method gives p10=1.0068, accurate within 0.001.
                        Problem 12: n>= 12, p12=1.3787
    Section 2.3: Problem 6c: p0=2 gives p4=2.370687; p0=4 gives p4=3.722113
                        Problem 8(with 6c):  (i) p0=2, p1=3 gives p6=2.370687; p0=3, p1=4 gives p7=3.722113
    Section 2.4: Problem 4a: alpha=1, lambda=1, linear convergence.
    Section 3.2: Problem 8: The second forward-difference of P at 10 is 1140.
    Section 3.3: Problem 2c: H3(-1/3) = 0.1745185 (approximation), f(-1/3) = 0.17451852 (exact).
    Section 3.4: Problem 2: s(x)=x  on [0,2].
                       Problem 8: a=4, b=4, c=-1, d=1/3.
    Section 4.1: Problem 2b:    x    Actual Error   Error Bound
                                           0.0   0.293            0.3
                                           0.2   0.2694          0.2779
                                           0.4   0.2602          0.2779
     Section 4.3: Problem 12: c0=1/3, c1=4/3, c2=1/3
     Section 4.4: Problem 4: a) 0.421582; b) 0.4227162; c) 0.4249845
     Section 4.7: Problem 2h: 0.6427011
     Section 5.2: Problem 4a:    t       Actual error
                                            1.2     0.0066879
                                            1.5     0.0095942
                                            1.7     0.0102229
                                            2.0     0.0105806
                         Problem 6c: h<0.029
     Section 5.4: Problem 2c:    ti          wi
                                           1.25      2.7767857
                                            1.5       3.6042017
                                           1.75      4.4736520
                                           2.00      5.3790494
      Section 6.1: Problem 2a: x1=1, x2=-0.98, x3= 2.9;
                         Problem 6: a) alpha=1, b) alpha=-1, c) x1=-1/(1-alpha), x2=1, x3= 1/(1-alpha)
      Section 6.3: Problem 2b: 1,1,1
      Section 6.4: Problem 6: alpha=6
      Section 6.6: Problem 10: alpha>8/7